The correct option is A True
Consider PR meets BD at O
In △, BDC and BOR,
∠B=∠B (Common)
∠BDC=∠BOR (Corresponding angles of parallel lines)
∠BCD=∠BRO (Corresponding angles of parallel lines)
thus, △BDC∼△BOR bt AAA
Thus, BDOB=BCBR
2=BCBR (O is the mid point of BD)
BR=12BC
Hence, R is the mid point BC