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Question

State True or False.
$$(x^2-3x)^2-5(x^2+3x)-y(x^2+3x)+5y$$$$ \ = \ (x^2+3x-5)(x^2+3x-y)$$


A
True
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B
False
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Solution

The correct option is A True
We have, $$(x^2+3x)^2-5(x^2+3x)-y(x^2+3x)+5y$$
$$=(x^2+3x)[(x^2+3x)-5]-y[(x^2+3x)-5]$$
$$=(x^2+3x-5)(x^2+3x-y)$$

Mathematics

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