Question

State True or False.

$(x-y{)}^3+(y-z{)}^3+(z-x{)}^3=$$3(x+y)(y-z)(z+x)$

• A. True
• B. False

Answer 1

The correct option is B False

Formula used: $If(a+b+c)=0,then{a}^3+b^3+c^3=3abc$
Now, $(x-y)+(y-z)+(z-x)=0$
$\Rightarrow (x-y{)}^3+(y-z{)}^3+(z-x{)}^3=3(x-y\left)\right(y-z\left)\right(z-x)$ (by above formula.)