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Question

State two multiples and two submultiples of the unit of electrical potential and electric current.


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Solution

Step 1: Multiple Units of,

Electric potential:

  1. KV(kilovolt)=103V
  2. MV(Megavolt)=106V

Electric current:

  1. KA(kiloampere)=1000A
  2. MA(Megaampere)=106A

Step 2: Submultiple Units of,

Electric potential: ­­

  1. mV=millivolt=10-3V
  2. µV=microvolt=10-6V

Electric current:

  1. mA=milliampere=10-3A
  2. µA=microampere=10-6A

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