State whether following statement is true or false.
If $A$ is a square matrix of order $n$ , then $| A d j (A d j A) |$ is of order $(n^{2})$ .

True

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False

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Solution

The correct option is B False

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Similar questions

A

n

| a d j (a d j A) | = \pm 1

| a d j (a d j A) | = {| A |}^{n^{2} - 1}

A = ⎡ ⎢ ⎣ \begin{matrix} 3 & - 3 & 4 2 & - 3 & 4 0 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦

a d j (a d j A) = A

a d j (a d j A) = {| A |}^{n - 2} A

A

2

a d j (a d j A)

A

adj(adj A) =

^{2}

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