State whether given statement is true or false:
Given reaction is for preparing $S O_{2}$ such that the oxidation state of sulphur is not effected.

$S + O_{2} ⟶ S O_{2}$

True

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False

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Solution

The correct option is B False
$S + O_{2} ⟶ S O_{2}$

Here oxidation state of sulphur changes from $0$ to $+ 4$ . In normal sulphur, it is $0$ . But in $S O_{2}$ , oxidation is $+ 4$ .

Thus, the given statement is false.

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