The correct option is A True
Let a ΔABC in which ∠B=90∘, AC be 12k and AB be 5k, where k is a positive real number.
By pythagoras theorem we get,
AC2=AB2+BC2
(12k)2=(5k)2+BC2
BC2+25k2=144k2
BC2=119k2
Such a triangle is possible as it will follow the pythagoras theorem.