The correct option is
A True
ABCD is a triangle where E and F are mid-points of AB and AC respectively.
Since AB∥CD with transversal ED
∠AEF=∠CDF (alternate angles) .........(1)
In △AEF and △CDF
∠AEF=∠CDF from (1)
∠AFE=∠CFD (vertically opposite angles)
AF=CF as F is the mid-point of AC
∴△AEF≅△CDF using AAS rule
So,EA=DC by CPCT
But EA=EB since E is the mid-point of AB
Hence,EB=DC
Now,in EBCD,EB∥DC and EB=DC
Thus, one pair of opposite sides are equal and parallel.
Hence,EBCD is a parallelogram.
Since opposite sides of parallelogram are parallel.
So,ED∥BC
∴EF∥BC
Hence the line segment joining the midpoint of two sides of a triangle is parallel to the third side.