Question

State whether the following statement is True or False?
Two sides $AB,BC$ and median $AM$ of one triangle $ABC$ are respectively equal to sides $PQ$ and $QR$ and median $PN$ of $△PQR$. then
$△ABM\cong △PQN$

• A. True
• B. False

Answer 1

The correct option is A True

In $△ABM$ and $△PQN$

$AB=PQ$

$BC=QR$

$AM=PN$

$AM$ is the median of $△ABC$

So, $BM=CM=\frac{1}{2}BC$

$PN$ is the median of $△PQR$

So, $QN=RN=\frac{1}{2}QR$

Therefore,

$BM=QN$

Hence,

$△ABM\cong △PQN$ {By SSS congruence}