You visited us 52 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Efficiency of Machines

State whether...

Question

State whether the given statement is correct or not.
Work done by kinetic friction on a body always results in a loss of its kinetic energy.

Open in App

Solution

According to given statement,
The work done against the direction of friction reduces the velocity of a body. Hence, there is a loss of kinetic energy of the body.
Hence, by using work energy Principle,Work done by all forces = Change in K.E
Therefore,
Work done by Friction is negative, it results in decrease of K.E
Final Answer: Yes.

Suggest Corrections

Similar questions

Underline the correct alternative:

(a) When a conservative force does positive work on a body, the potential energy of the body increases/decreases/remains unaltered.

(b) Work done by a body against friction always results in a loss of its kinetic/potential energy.

(c) The rate of change of total momentum of a many-particle system is proportional to the external force/sum of the internal forces on the system.

(d) In an inelastic collision of two bodies, the quantities which do not change after the collision are the total kinetic energy/total linear momentum/total energy of the system of two bodies.

Underline the correct alternative :

(a) When a conservative force does positive work on a body, the potential energy of the body increases / decreases / remains unaltered.

(b) Work done by a body against friction always results in a loss of its kinetic / potential energy.

(c) The rate of change of total momentum of a many-particle system is proportional to the external force / sum of the internal forces on the system.

(d) In an inelastic collision of two bodies, the quantities which do not change after the collision are the total kinetic energy / total linear momentum / total energy of the system of two bodies.

A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1.

Compute the

(a) work done by the applied force in 10 s,

(b) work done by friction in 10 s,

(d) change in kinetic energy of the body in 10 s,

and interpret your results.

Q. A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the (a) work done by the applied force in 10 s, (b) work done by friction in 10 s, (c) work done by the net force on the body in 10 s, (d) change in kinetic energy of the body in 10 s, and interpret your results.

State if each of the following statements is true or false. Give reasons for your answer.

(a) In an elastic collision of two bodies, the momentum and energy of each body is conserved.

(b) Total energy of a system is always conserved, no matter what internal and external forces on the body are present.

(d) In an inelastic collision, the final kinetic energy is always less than the initial kinetic energy of the system.

Join BYJU'S Learning Program

Explore more

Efficiency of Machines

Standard VIII Physics

Join BYJU'S Learning Program

State whether the given statement is correct or not. Work done by kinetic friction on a body always results in a loss of its kinetic energy.

State whether the given statement is correct or not.
Work done by kinetic friction on a body always results in a loss of its kinetic energy.