State whether the given statement is true or false
$(3 a^{2} - 8 a b - 2 b^{2}) - (3 a^{2} - 4 a b + 6 b^{2}) = - 4 a b - 8 b^{2}$

True

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False

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Solution

The correct option is A True
Let us solve the given expression $(3 a^{2} - 8 a b - 2 b^{2}) - (3 a^{2} - 4 a b + 6 b^{2})$ as shown below:

$(3 a^{2} - 8 a b - 2 b^{2}) - (3 a^{2} - 4 a b + 6 b^{2}) = 3 a^{2} - 8 a b - 2 b^{2} - 3 a^{2} + 4 a b - 6 b^{2} = (3 a^{2} - 3 a^{2}) + (- 8 a b + 4 a b) + (- 2 b^{2} - 6 b^{2}) (C o m b i n i n g l i k e t e r m s) = (3 - 3) a^{2} + (- 8 + 4) a b + (- 2 - 6) b^{2} = - 4 a b - 8 b^{2}$

Hence, $(3 a^{2} - 8 a b - 2 b^{2}) - (3 a^{2} - 4 a b + 6 b^{2}) = - 4 a b - 8 b^{2}$ .

Suggest Corrections

Similar questions

3 a^{2} - 4 a b + 6 b^{2} - (3 a^{2} - 8 a b - 2 b^{2})

3 a^{2} + 8 a b + 2 b^{2}, 3 a^{2} + 4 a b + 6 b^{2}

State True or False:

On subtracting $a^{2} + a b + b^{2}$ from $4 a^{2} - 3 a b + 2 b^{2}$ , the answer is $3 a^{2} - 4 a b + b^{2}$ .

(a - 2 b)^{2}

a^{2} - 4 a b + 4 b^{2}

(2 a + b)^{2}

4 a^{2} + 4 a b + b^{2}

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