State whether the given statement is true or false.
$(- 6)^{0}$ = –1

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Solution

R.H.S. = −1
L.H.S. = $(- 6)^{0}$
= 1 ≠ −1 [∵ $a^{0}$ = 1 ; (𝑎 ≠ 0)]
∴ L.H.S. ≠ R.H.S.
Hence, the given statement is false.

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