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Ellingham Diagram

State whether...

Question

State whether the given statement is True or False.
$C u O$ can't be reduced by carbon but it can be reduced by $H_{2}$ .
given : $Δ G_{f}^{\circ}$ for $C u O =$ -129.7 kJ $m o l^{- 1}$ , $C O =$ - 137.2 kJ $m o l^{- 1}$ $H_{2} O$ = - 237.2 kJ $m o l^{1}$

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Solution

$C u O + C \to C u + C O$
$Δ G^{\circ} = Δ G_{f}^{\circ} (C O) - Δ G_{f}^{\circ} (C u O)$
$= - 137.2 + 129.7 = - 7.5 k J$
$C u O + H_{2} \to C u + H_{2} O$
$Δ G^{\circ} = Δ G_{f}^{\circ} (H_{2} O) - Δ G_{f}^{\circ} (C u O)$
$= - 237.2 + 129.7 = - 366.9 k J$
Both the reactions are spontaneous means $C u O$ can be reduced by both $C$ and $H_{2}$ and thus the given statement is $F a l s e .$

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6 k J m o l^{- 1} K^{- 1}

25^{o} C, △ G_{f}^{o} o f A l_{2} O_{3} (s) = - 1582 k J m o l^{- 1}; △ H_{f}^{o} o f L i_{2} O (s) = 1244 k J / m o l a n d △ H_{f}^{o}

N a_{2} O (s) = 1411 k J / m o l .

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CuO + H_{2} \to Cu + H_{2} O

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4 A l (s) + 3 O_{2} (s) + 6 H_{2} O + 4 O H^{-} \to 4 [A l (O H)_{4}^{-}]

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6 k J m o l^{- 1} K^{- 1}

25^{o} C, △ G_{f}^{o} o f A l_{2} O_{3} (s) = - 1582 k J m o l^{- 1}; △ H_{f}^{o} o f L i_{2} O (s) = 1244 k J / m o l a n d △ H_{f}^{o}

N a_{2} O (s) = 1411 k J / m o l .

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