Question

State whether the given statement is true or false:

Dipositive zinc exhibits paramagnetism due to loss of two electrons from $3d$-orbitals of neutral atom.

Answer 1

$Z{n}^{2+}$ losses electrons from the $4s^2$ orbital and does not have any unpaired electron. Therefore it is diamagnetic.
${zn}^{2+}$

The oxidation number of $Zn$ is $+2$.

$z=30$

$Zn=\left[Ar\right]{3d}^{10}{4s}^2$

${Zn}^{2+}=\left[Ar\right]{3d}^{10}$

$\uparrow \downarrow$

$\uparrow \downarrow$

$\uparrow \downarrow$

$\uparrow \downarrow$

$\uparrow \downarrow$

No unpaired electron present; hence diamagnetic.

Hence,given statement is false.