Question

State whether the given statement is true or false:

${\left(\frac{\sqrt{7}}{6\sqrt{2}}\right)}^2$ is a prime.

• A. True
• B. False

Answer 1

The correct option is B False

${\left(\frac{\sqrt{7}}{6\sqrt{2}}\right)}^2$
$=\left(\frac{\sqrt{7}}{6\sqrt{2}}\right)\times \left(\frac{\sqrt{7}}{6\sqrt{2}}\right)$
$=\frac{7}{6\times 6\times 2}$
$=\frac{7}{72}$ which is a rational number.

Hence, the given statement is false.