Question

State whether the given statement is true or false:

Highest fluorides of oxygen is $O{F}_2$ whereas sulphur forms $S{F}_6$.

• A. True
• B. False

Answer 1

The correct option is A True

sulfur can use its 3d-orbitals to expand its octet and accomodate more than 8 valence electrons in outermost shell but oxygen does not have 3d orbital.

Sulphur can use its 3d orbitals to make more than 4 covalent bonds. Oxygen can’t use “d” orbitals, because they don’t exist in its outermost

Highest oxidation state of oxygen is +2, whereas highest oxidation state of S is +6 so oxygen forms $O{F}_2$ and S forms $S{F}_6$.