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Question

State whether the given statement is true or false If x0 be any real number . r1=x,2x,3x r2=2x+1,2x+3,x+1 and r3=3x+5,x+5,x+2
If the vectors r1,r2,r3 are coplanar.

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Solution

(r1r2r3)=∣ ∣x2x3x2x+12x+3x+13x+5x+5x+2∣ ∣
Expand the above determinant
(r1r2r3)=x(15x2+31x+37)
Now quadratic expression 15x2+31x+37 is such that its
Δ=(31)260(37)=ive
and hence its sign is same as that of the coefficient of first term i.e.,15 i.e, +ive.
Also x0 is a real number.
(r1.r2.r3)0.
Hence the vectors are non-coplanar.

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