State whether the given statement is true or false If x≠0 be any real number . r1=x,2x,−3xr2=2x+1,2x+3,x+1 and r3=3x+5,x+5,x+2 If the vectors r1,r2,r3 are coplanar.
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Solution
(r1r2r3)=∣∣
∣∣x2x−3x2x+12x+3x+13x+5x+5x+2∣∣
∣∣ Expand the above determinant
∴(r1r2r3)=x(15x2+31x+37) Now quadratic expression 15x2+31x+37 is such that its
Δ=(31)2−60(37)=−ive and hence its sign is same as that of the coefficient of first term i.e.,15 i.e, +ive. Also x≠0 is a real number.
∴(r1.r2.r3)≠0. Hence the vectors are non-coplanar.