State whether the given statement is true or false:
In $△ A B C$ and $△ D E F, A B = D E, B C = E F$ and $∠ B = ∠ E$ . The triangles are congruent by $S S S$ test.

True

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False

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Solution

The correct option is B False
In $△$ ABC and $△$ DEF,
$A B = D E$ (Given)
$B C = E F$ (Given)
$∠ B = ∠ E$ (Given)
Hence, $△ A B C ≅ △ D E F$ (By SAS postulate)

So, the given statement is False.

Suggest Corrections

Similar questions

State true/false:

If in $Δ A B C$ and $Δ D E F$ , AB = DE, BC = DE, BC = EF and $∠ B = ∠ E$ , then both the triangles are congruent.

△ A B C

△ D E F

∠ B = ∠ E, A B = D E, B C = E F

Δ A B C a n d Δ D E F; A B = E F, B C = D F a n d ∠ B = ∠ F

△

△

Δ A B C

∠ A = ∠ D

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