State whether the given statement is true or false:

The compound $Y {B a}_{2} {C u}_{3} O_{7}$ which shows super conductivity has copper in oxidation state $+ \frac{7}{3}$ . Assume that the rare earth element yttrium is in its usual $+ 3$ oxidation state.

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Solution

Given +3 oxidation state of yttrium and +2 oxidation state of Barium, the resultant is $[C u_{3} O_{7}]^{- 7}$ .

Therefore Copper must have an oxidation state : $3 + (2 \times 2) + 3 x - 14 = 0$

= $\frac{+ 7}{3}$

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Similar questions

Q. In the compound

Y {B a}_{2} {C u}_{3} O_{7}

which shows superconductivity, what is the oxidation state of

C u

?
Assume that the rare earth element yttrium is in its usual +3 oxidation state.

Q. What is the oxidation state of copper in the compound,

Y B a_{2} C u_{3} O_{7}

which shows super conductivity? Assume that the rare earth element, yttrium is in its usual

+ 3

oxidation state.

The compound Y $B a_{2} C u_{3} O_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state

Q. The compound

Y B a_{2} C u_{3} O_{7}

, which shows super conductivity has copper in oxidation state of

\frac{7}{3}

.
Assume that the rare earth element ytterbium is in its usual

+ 3

oxidation state.
If true enter 1, else enter 0.

Q. The compound

{Y b B a}_{2} {C u}_{3} O_{7}

, which shows superconductivity has copper in oxidation state

x

, then

x

is :
(Assume that the rare earth element ytterbium is in the usual

+ 3

oxidation state)

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State whether the given statement is true or false:The compound YBa2Cu3O7 which shows super conductivity has copper in oxidation state +73. Assume that the rare earth element yttrium is in its usual +3 oxidation state.

Given +3 oxidation state of yttrium and +2 oxidation state of Barium, the resultant is [Cu3O7]−7. Therefore Copper must have an oxidation state : 3+(2×2)+3x−14=0 =+73

State whether the given statement is true or false:

The compound $Y {B a}_{2} {C u}_{3} O_{7}$ which shows super conductivity has copper in oxidation state $+ \frac{7}{3}$ . Assume that the rare earth element yttrium is in its usual $+ 3$ oxidation state.

Given +3 oxidation state of yttrium and +2 oxidation state of Barium, the resultant is $[C u_{3} O_{7}]^{- 7}$ .

Therefore Copper must have an oxidation state : $3 + (2 \times 2) + 3 x - 14 = 0$

= $\frac{+ 7}{3}$