State whether the given statement is true or false
A triangle ABC in which DE||BC, and intersects AB in D and AC in E
Hence,
$\frac{A D}{D B} = \frac{A E}{E C}$

True

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False

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Solution

The correct option is A True
Since, $△ A B C ≅ △ M N P$ ,
By CPCT we can say that,
Side $A B ≅$ Side MN,
Side BC $≅$ Side NP,
Side AC $≅$ Side MP,
$∠ A ≅ ∠ M, ∠ B ≅ ∠ N, ∠ C ≅ ∠ P$

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Similar questions

\frac{A B}{A D} = \frac{A C}{A E}

\frac{A B}{D B} = \frac{A C}{E C}

△

\times

\times

∥

△ A B C

D E | | B C

A B

D

A C

E

\frac{A B}{A D} = \frac{A C}{A E}

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