State whether the given statement is true or false
If α+β−γ=π, then show that sin2α+sin2β−sin2γ=2sinαsinβcosγ.
A
True
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B
False
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Solution
The correct option is A True sin2α+sin2β−sin2γ=sin2α+(sin2β−sin2γ)=sin2α+sin(β+γ)sin(β−γ)=sin2α+sin(π−α)sin(β−γ)=sin2α+sinαsin2α=sinα(sinα+sin(β−γ))=sinα(sin(π−(β+γ))+sin(β−γ))=sinα(sin(β+y)+sin(β−γ))=sinα(2cosβcosγ)=2sinαsinβcosγ