Question

State whether the statement is True or False:

$(2x-\frac{1}{2x}{)}^2$ is equal to $4x^2-2+\frac{1}{4x^2}$.

• A. True
• B. False

Answer 1

The correct option is A True

Given, $(2x-\frac{1}{2x}{)}^2$.

We know, $(a-b{)}^2=a^2-2ab+b^2$.

Then,

$(2x-\frac{1}{2x}{)}^2={\left(2x\right)}^2-2(2x\left)\right(\frac{1}{2x})+(\frac{1}{2x}{)}^2=4x^2-2+\frac{1}{{4x}^2}.$

Therefore, the statement is true.

Hence, option $A$ is correct.