Question

State whether the statement is True or False.

The cube of $(x-\frac{1}{2})$ is equal to $x^3-\frac{3x^2}{2}+\frac{3x}{4}-\frac{1}{8}$.

• A. True
• B. False

Answer 1

The correct option is A True

${(a+b)}^3=a^3+b^3+3a^{2}b+3a{b}^2(x-\frac{1}{2}{)}^3=x^3-\frac{1}{8}+\frac{3}{4}x-\frac{3}{2}{x}^2$