Question

State whether the statement is True or False:

The square of $(a+\frac{1}{5a})$ is $a^2+1+\frac{1}{4a^2}$.

• A. True
• B. False

Answer 1

The correct option is B False

Given, $(a+\frac{1}{5a}{)}^2$.

We know, $(x+y{)}^2=x^2+2xy+y^2$.

Then,

$(a+\frac{1}{5a}{)}^2=a^2+2(a\left)\right(\frac{1}{5a})+(\frac{1}{5a}{)}^2=a^2+\frac{2}{5}+\frac{1}{25a^2}.$

Therefore, the statement is false.

Hence, option $B$ is correct.