State whether the statement is true or false.
The square of $(x - 2 y + 1)$ is equal to $x^{2} + 4 y^{2} + 1 - 4 x y - 4 y + 2 x$ .

True

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False

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Solution

The correct option is A True
$x - 2 y + 1$
Squaring we get,
$= (x - 2 y + 1)^{2}$
$= x^{2} + (- 2 y)^{2} + 1^{2} + 2 (x) (- 2 y) + 2 (- 2 y) (1) + 2 (1) (x)$
$= x^{2} + 4 y^{2} + 1 - 4 x y - 4 y + 2 x$

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