Question 42
State whether the statements are True or False.
Median of the data may or may not be from the given data.

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Solution

True
e.g.
(i) 2, 4, 6, 8, 10
Here, n = 5(odd)
Median = Value of $(\frac{n + 1}{2})$ th observation = Value of $(\frac{5 + 1}{2})$
= Value of 3rd observation = 6
(ii) 4, 6, 8, 8, 12, 14, 15, 16
Here, n = 8 (even)
$M e d i a n = \frac{V a l u e o f (\frac{n}{2}) t h o b s e r v a t i o n + V a l u e o f (\frac{n}{2} + 1) t h o b s e r v a t i o n}{2} = \frac{V a l u e o f 4 t h o b s e r v a t i o n + V a l u e o f 5 t h o b s e r v a t i o n}{2} = \frac{8 + 12}{2} = \frac{20}{2} = 10$

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Median

Standard VII Mathematics

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Question 42 State whether the statements are True or False. Median of the data may or may not be from the given data.

Question 42
State whether the statements are True or False.
Median of the data may or may not be from the given data.