Question

State whether the value of $\frac{q^3}{p^3-q^3}$ is $\frac{125}{91}$ if true then enter $1$ else enter $0$.

Answer 1

Given that,

$\frac{p}{q}=\frac{6}{5}$

$\therefore p=6xandq=5x$

$\frac{q^3}{p^3-q^3}$

$=\frac{{\left(5x\right)}^3}{{\left(6x\right)}^3-{\left(5x\right)}^3}=\frac{125x^3}{91x^3}$

$=\frac{125}{91}$

Hence the answer is 1