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Factorisation by Regrouping Terms

State whether...

Question

State whether True or False.
Divide: $- 4 a^{2} b^{3} - 8 a b^{2} + 6 a b$ by $- 2 a b$ , then answer is $2 a b^{2} + 4 b - 3$ .

True

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False

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Solution

The correct option is A True
$\Rightarrow \frac{- 4 a^{2} b^{3} - 8 a b^{2} + 6 a b}{- 2 a b}$
In $- 4 a^{2} b^{3} - 8 a b^{2} + 6 a b$ we take $- 2 a b$ common then
$\Rightarrow \frac{- 2 a b (2 a b^{2} + 4 b - 3)}{- 2 a b}$
$\Rightarrow 2 a b^{2} + 4 b - 3$

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