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Byju's Answer
Standard IX
Mathematics
Factorisation by Regrouping Terms
State whether...
Question
State whether True or False.
Divide:
−
4
a
2
b
3
−
8
a
b
2
+
6
a
b
by
−
2
a
b
, then answer is
2
a
b
2
+
4
b
−
3
.
A
True
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B
False
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Solution
The correct option is
A
True
⇒
−
4
a
2
b
3
−
8
a
b
2
+
6
a
b
−
2
a
b
In
−
4
a
2
b
3
−
8
a
b
2
+
6
a
b
we take
−
2
a
b
common then
⇒
−
2
a
b
(
2
a
b
2
+
4
b
−
3
)
−
2
a
b
⇒
2
a
b
2
+
4
b
−
3
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