State whether true or false :
Electric field calculated by a Gauss law is the field due to only those charges which are enclosed inside the Gaussian surface.

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B False
False.
Gauss Law: $\int \to E . d \to A = \frac{Q_{e n c l o s e d}}{ϵ_{0}}$
So, if charge enclosed is zero that doesn't mean that $E = 0$ . Therefore, electric field is not present only due to enclosed charge inside the Gaussian surface.

Suggest Corrections

Similar questions

Comment on the correctness of the following two statements

Statement I => The electrical field calculated by Gauss’s law is the field only due to the charges inside the Gaussian surface.

Statement II => The flux of the electric field through a closed surface due to all the charges (inside and outside the surface), is equal to the flux only due to the charges enclosed by the surface.

Q. State whether true or false :

Electric flux through a closed surface is equal to total flux due to all the charges enclosed within that surface only.

Q. Assertion :Gauss law holds good only to those closed surfaces which is enclosing non-zero electric charge. Reason: The electric flux through a closed surface is unaltered due to the presence of outside charge.

Q. Assertion :In a given situation of arrangement of charges, an extra charge is placed outside the Gaussian surface. In the Gauss Theorem

\oint \to E . d \to s = \frac{Q_{i n}}{ϵ_{0}}

Q_{i n}

remains same whereas electric field

\to E

at the site of the element is changed. Reason: Electric field

\to E

at any point o the Gaussian surface is due to inside charge only.

Q. State whether the given statement is True or False :

Gauss's law implies that the total electric flux through a closed surface is zero if no charge is enclosed by the surface.

Join BYJU'S Learning Program

State whether true or false :Electric field calculated by a Gauss law is the field due to only those charges which are enclosed inside the Gaussian surface.

The correct option is B FalseFalse.Gauss Law: ∫→E.d→A=Qenclosedϵ0So, if charge enclosed is zero that doesn't mean that E=0. Therefore, electric field is not present only due to enclosed charge inside the Gaussian surface.

State whether true or false :
Electric field calculated by a Gauss law is the field due to only those charges which are enclosed inside the Gaussian surface.

The correct option is B False
False.
Gauss Law: $\int \to E . d \to A = \frac{Q_{e n c l o s e d}}{ϵ_{0}}$
So, if charge enclosed is zero that doesn't mean that $E = 0$ . Therefore, electric field is not present only due to enclosed charge inside the Gaussian surface.