State whether True or False.
Factorization of $1 - 3 x - 3 y - 4 (x + y)^{2}$ is $(1 - 4 x - 4 y) (1 + x + y)$ .

True

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False

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Solution

The correct option is A True
$F a c t o r i z i n g 1 - 3 x - 3 y - 4 (x + y)^{2} = 1 - 3 (x + y) - 4 (x + y)^{2} = 1 + (x + y) - 4 (x + y) - 4 (x + y)^{2} = 1 (1 + (x + y)) - 4 (x + y) (1 + (x + y)) = (1 - 4 x - 4 y) (1 + x + y)$ \\

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