Factorization of 15(2x−y)2−16(2x−y)−15 is (6x−3y−5)(10−5y+3).
A
True
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B
False
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Solution
The correct option is A True Factorizing15(2x−y)2−16(2x−y)−15,=15(2x−y)2−25(2x−y)+9(2x−y)−15=5(2x−y)(3(2x−y)−5)+3(3(2x−y)−5)=(5(2x−y)+3)(3(2x−y)−5)=(6x−3y−5)(10x−5y+3)