State whether true or false:
If $x^{5} = 32$ , then $x = 2$

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
TRUE:
Odd exponents preserve the sign of the original expression. Therefore, if $x^{5}$ is positive, then $x$ must itself be positive. If $x^{5} = 32$ , then $x$ must be $2$

Suggest Corrections

Similar questions

(x - 3)^{2} = 25

x

8

- 2

256 = 16^{n}

n = 2

x^{3} = 11

x = \sqrt[3]{11}

81 = 3^{n}

n = 5

4^{2 x} = \frac{1}{32}

- \frac{5}{4}

Join BYJU'S Learning Program