Question

State whether True or False.

Multiply: $2a^3-3a^{2}b$ and $-\frac{1}{2}a{b}^2$.

The value is $-a^4{b}^2+\frac{3}{2}{a}^3{b}^3$.

• A. True
• B. False

Answer 1

The correct option is A True

As given $2a^3-3a^{2}b$ and $-\frac{1}{2}a{b}^2$
$\Rightarrow 2a^3\times -\frac{1}{2}a{b}^2-3a^{2}b\times -\frac{1}{2}a{b}^2$
$\Rightarrow -a^3\times a{b}^2+\frac{3}{2}{a}^{2}b\times a{b}^2$
$\Rightarrow -a^{3+1}{b}^2+\frac{3}{2}{a}^{2+1}{b}^{1+2}$
$\Rightarrow -a^4{b}^2+\frac{3}{2}{a}^3{b}^3$