Question

State whether True or False.

Multiply: $-\frac{3}{2}{x}^5{y}^3$ and $\frac{4}{9}{a}^2{x}^{3}y$.

The answer is $-\frac{2}{3}{a}^2{x}^8{y}^4$.

• A. True
• B. False

Answer 1

The correct option is A True

$-\frac{3}{2}{x}^5{y}^3\times \frac{4}{9}{a}^2{x}^{3}y$
$=(-\frac{3}{2})\left(\frac{4}{9}\right)a{x}^{5+3}{y}^{(}3+1)$
$=-\frac{2}{3}{a}^2{x}^8{y}^4$