State whether true or false
The correct order regarding the electronegativity of hybrid orbitals of carbon is
sp > ${s p}^{2}$ > ${s p}^{3}$

sp<sp²<sp³

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sp<sp²> sp³

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Solution

The correct option is A
sp<sp²<sp³

With the increase in % of s-character in hybrid orbitals the electronegativity of the hybrid orbitals increases.

sp - 50% s character,

${s p}^{2}$ - 33.3 % s character

${s p}^{3}$ - 25% s character.

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