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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
State whether...
Question
State whether True or False.
The H.C.F. and L.C.M. of:
4
x
2
y
z
3
and
6
x
3
y
2
z
2
is
2
x
2
y
z
2
;
12
x
3
y
2
z
3
If true then enter
1
and if false then enter
0
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Solution
Factorizing
4
x
2
y
z
3
and
6
x
2
y
2
z
2
4
x
2
y
z
3
=
2
×
2
×
x
2
×
y
×
z
3
6
x
2
y
2
z
2
=
6
×
x
2
×
y
2
×
z
2
H.C.F.
=
2
×
x
2
×
y
×
z
2
=
2
x
2
y
z
2
L.C.M.
=
12
×
x
2
×
y
2
×
z
3
=
12
x
2
y
2
z
3
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0
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State whether True or False.
The H.C.F. and L.C.M. of:
a
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and
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c
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is
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If true then enter
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and if false then enter
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and if false then enter
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State whether True or False.
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a
x
y
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3
a
y
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and
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x
y
is
y
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If true then enter
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and if false then enter
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State whether True or False.
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3
a
2
b
2
c
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6
a
3
b
and
a
3
b
2
c
3
is
a
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b
;
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b
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If true then enter
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and if false then enter
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