wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

State whether true or false:
x2=11, then x=11

A
True
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
False
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B False
FALSE:
Even exponents hide the sign of the original number, because they always result in a positive value. If x2=11, then |x|=11. Thus, x could be either 11 or 11

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Indices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon