Question

State whether true or false

Factors of $\frac{x^2}{16}-\frac{y^2}{25}$ are$(\frac{x}{4}+\frac{y}{5})(\frac{x}{4}+\frac{y}{5})$

• A. True
• B. False

Answer 1

The correct option is B False

$\frac{x^2}{16}-\frac{y^2}{25}$
Using,
$(a^2-b^2)=(a+b)(a-b)$
$=(\frac{x}{4}{)}^2-(\frac{y}{5}{)}^2$
$=(\frac{x}{4}+\frac{y}{5})(\frac{x}{4}-\frac{y}{5})$