State which of the following are not surds:

\sqrt{15}

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\sqrt{64}

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\sqrt{17}

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\sqrt{19}

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Solution

The correct option is D $\sqrt{64}$
$\sqrt[2]{64} = \sqrt{64} = 8$ , which is an integer, thus not a Surd.
Options A, C and D can not be given simplified to rational number, hence they are surd

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