It is known that the sum of all the probabilities in a probability distribution is one.
(i) Sum of the probabilities =0.4+0.4+0.2=1
Therefore, the given table is a probability distribution of random variables.
(ii) It can be seen that for X=3,P(X)=−0.1
It is known that probability of any observation is not negative. Therefore, the given table is not a probability distribution of random variables.
(iii) Sum of the probabilities =0.6+0.1+0.2=0.9≠1
Therefore, the given table is not a probability distribution of random variables.
(iv) Sum of the probabilities =0.3+0.2+0.4+0.1+0.05=1.05≠1
Therefore, the given table is not a probability distribution of random variables.