Question

State whther the following statement is true or false
In $△ABC$, $AB=AC$; $BE\perp AC$ and $CF\perp AB$. Then $BE=CF$

• A. True
• B. False

Answer 1

The correct option is A True

In $△BFC$ and $△CEB$

$\angle BFC=\angle CEB={90}^{\circ }$

$\angle FBC=\angle ECB$ {angle opp. to equal sides AC and AB}

$BC=BC$ {Common}

$△BFC\cong △CEB$ {By using SAA Congruence}

Therefore,

$BE=CF$