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Byju's Answer
Standard XII
Mathematics
Logarithmic Inequalities
Statement -1:...
Question
Statement
−
1
:
0
<
x
<
y
⇒
log
a
x
>
log
a
y
, where
a
>
1
.
Statement
−
2
:
When
a
>
1
,
log
a
x
is an increasing function.
A
Statement
−
1
is true, Statement
−
2
is true; Statement
−
2
is a correct explanation for Statement
−
1
.
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B
Statement
−
1
is true, Statement
−
2
is true; Statement
−
2
is NOT a correct explanation for Statement
−
1
.
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C
Statement
−
1
is true, Statement
−
2
is false.
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D
Statement
−
1
is false, Statement
−
2
is true.
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Solution
The correct option is
D
Statement
−
1
is false, Statement
−
2
is true.
When
a
>
1
,
log
a
x
is an increasing function.
∴
x
<
y
⇒
log
a
x
<
log
a
y
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1
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