STATEMENT-1 : $B e$ and $A l$ form amphoteric oxides.
STATEMENT-2 : $B e$ and $A l$ are metalloids.

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is False

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STATEMENT-1 is False, STATEMENT-2 is True

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Solution

The correct option is D STATEMENT-1 is True, STATEMENT-2 is False
$B e$ and $A l$ form the amphoteric oxides, $B e O$ and $A l_{2} O_{3}$ respectively. These oxides can behave both as base as well as acids.

Aluminium $(A l)$ is a lightweight silvery-white metal and beryllium is also a steel-gray metal which is quite brittle at room temperature and resembles some of the properties of aluminium.

Hence, STATEMENT-1 is true and STATEMENT-2 is false.
Therefore, Option (C) is correct.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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