Statement 1: $B F_{3}$ has a tetrahedral geometry.
Statement 2: The central $B$ atom does not have a complete stable octet.

Both Statement 1 and Statement 2 are correct and Statement 2 is the correct explanation of Statement 1.

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Both Statement 1 and Statement 2 are correct, but Statement 2 is NOT the correct explanation of Statement 1.

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Statement 1 is correct, but Statement 2 is not correct.

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Statement 1 is not correct, but Statement 2 is correct.

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Solution

The correct option is D Statement 1 is not correct, but Statement 2 is correct.
Boron trifluoride only has six valence electrons and is one of the relatively rare second period covalent molecules that disobeys the octet rule. There are three bonded groups and so no lone pairs. Six electrons implies three electron pairs and therefore a trigonal geometry.

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Statement 1: BF3 has a tetrahedral geometry.Statement 2: The central B atom does not have a complete stable octet.

Statement 1: $B F_{3}$ has a tetrahedral geometry.
Statement 2: The central $B$ atom does not have a complete stable octet.