Statement-1: Decomposition of $H_{2} O_{2}$ is disproportionation reaction.
Statement-2: Hydrogen undergoes both oxidation and reduction simultaneously.

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

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Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

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Statement-1 is true, Statement-2 is false

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Statement-1 is false, Statement-2 is true

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Solution

The correct option is C
Statement-1 is true, Statement-2 is false

Oxygen undergoes both Oxidation (from -1 to 0 in $O_{2}$ ) and Reduction(from -1 to -2 in $H_{2} O$ ) and not Hydrogen.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

N H_{3}

P H_{3}

N H_{3}

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