STATEMENT-1 - limx - 0-1 - cos 2 x-x does not exist-STATEMENT-2 - fx - -1 - cos 2 x-x is not defined at x - 0-

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Substitution Method to Remove Indeterminate Form

STATEMENT-1 :...

Question

STATEMENT-1 : $lim x \to 0 \frac{\sqrt{1 - cos 2 x}}{x}$ does not exist.
STATEMENT-2 : $f (x) = \frac{\sqrt{1 - cos 2 x}}{x}$ is not defined at $x = 0$ .

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is False

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STATEMENT-1 is False, STATEMENT-2 is True

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

- 1 :

x^{{log}_{x} (3 - x)^{2}} = 25

x = - 2

- 2 :

a^{{log}_{a} x} = x

a > 0, x > 0

a \neq 1

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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