Statement 1: Glucose breaks down into a 3-carbon compound in the cytoplasm of the cell.

Statement 2: A pyruvate molecule breaks down into 3-molecules of carbon dioxide in mitochondria of the cell.

Statement 1 and Statement 2 both are incorrect

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Statement 1 is incorrect and Statement 2 is correct

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Statement 1 is correct and Statement 2 is incorrect

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Both Statement 1 and Statement 2 are correct

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Solution

The correct option is D
Both Statement 1 and Statement 2 are correct

During respiration, glucose molecule, a 6-carbon compound, breaks down into two molecules of a 3-carbon compound called pyruvate. Glycolysis or breakdown of glucose takes place in the cytoplasm of cell and pyruvate breaks further in mitochondria, forming carbon dioxide and energy.

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Similar questions

Statement 1: Glucose breaks down into a 3-carbon compound in the cytoplasm of the cell.

Statement 2: A pyruvate molecule breaks down into 3-molecules of carbon dioxide in mitochondria of the cell.

Q. The breakdown of glucose into pyruvate takes place in the ____________ while pyruvate breaks down in the _____________ into water and carbon dioxide with release of energy.

Q. Glucose is broken down into a 3-carbon compound called in the cytoplasm of the cell.

Q. Where in the cell does the pyruvate break down to produce carbon dioxide and water?

Question 12
The correct sequence of anaerobic reactions in yeast is

(a) $G l u c o s e c y t o p l a s m - ----- \to P y r u v a t e m i t o c h o n d r i a - ------- \to E t h a n o l + C a r b o n d i o x i d e$
(b) $G l u c o s e c y t o p l a s m - ----- \to P y r u v a t e c y t o p l a s m - ----- \to L a c t i c a c i d$
(c) $G l u c o s e c y t o p l a s m - ----- \to P y r u v a t e m i t o c h o n d r i a - ------- \to L a c t i c a c i d$
(d) $G l u c o s e c y t o p l a s m - ----- \to P y r u v a t e c y t o p l a s m - ----- \to E t h a n o l + C a r b o n d i o x i d e$

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