STATEMENT-1 : Guanine unites with cytosine with three hydrogen bonds but it forms only one hydrogen bond with thymine.
STATEMENT-2 : Guanine and cytosine are purines while that of thymine is a pyrimidine.

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is False

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STATEMENT-1 is False, STATEMENT-2 is True

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Solution

The correct option is C STATEMENT-1 is True, STATEMENT-2 is False
Option (C) is correct.
$S 1$ : Guanine unites with cytosine with three hydrogen bonds but it forms only one hydrogen bond with thymine. Within the $D N A$ double helix, $A$ forms 2 hydrogen bonds with $T$ on the opposite strand, and $G$ forms 3 hydrogen bonds with $C$ on the opposite strand.
$S 2$ : Guanine is purines while cytosine and thymine are pyrimidine.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

Statement 1: The four nitrogen bases in a DNA molecule are guanine, thymine adenine, cytosine.

Statement 2: Where adenine and thymine are purines and guanine and cytosine are pyrimidines.

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

N H_{3}

P H_{3}

N H_{3}

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