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Best Suited Measure of Central Tendency in Different Cases and the Empirical Relationship between Them

STATEMENT -1 ...

Question

STATEMENT -1 : Histogram is useful to determine graphically the value of mode.
STATEMENT -2 : The empirical relationship between average, median and mode is mode $=$ $3$ median $- 2$ mean.

Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1

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Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1

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Statement - 1 is True, Statement - 2 is False

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Statement - 1 is False, Statement - 2 is True

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Solution

The correct option is B Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1
Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1.
Reason :-
Empherical relationship between average, median, mode helps to find the other value using two of the values while Statement - 1 i.e. Histogram is use to graphically determine the value of mode only. Thus, Statement - 2 does not explain and relate to Statement - 1.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

N H_{3}

P H_{3}

N H_{3}

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