Question

Statement 1: On a curved path average speed of a particle can never be equal to average velocity.
Statement 2: Average speed is total distance travelled divided by total time. Whereas average velocity is, final velocity plus initial velocity divided by two.

• A. Statement-1 is True; Statement-2 is True; Statement -2 is a correct explanation for Statement-1.
• B. Statement-1 is True; Statement-2 is True; Statement -2 is NOT a correct explanation for Statement-1.
• C. Statement-1 is True; Statement-2 is False.
• D. Statement-1 is False; Statement-2 is True

Answer 1

The correct option is C Statement-1 is True; Statement-2 is False.

On a curved path, distance > displacement
$\therefore \text{Average speed}>\text{average velocity}$
Further, $\text{Average velocity}=\frac{\text{Total displacement}}{\text{Total time}}$
In case of curved path, since the initial and final velocities are vectors in different directions and acceleration is not constant so we cannot say that the average velocity is the mean of initial velocity and final velocity $\text{i.e}{V}_{av}\ne \frac{\overrightarrow{v_1}+\overrightarrow{v_2}}{2}$. It is only true when motion is in straight line and accleration is constant.